1=5x^2+4x

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Solution for 1=5x^2+4x equation:


Simplifying
1 = 5x2 + 4x

Reorder the terms:
1 = 4x + 5x2

Solving
1 = 4x + 5x2

Solving for variable 'x'.

Reorder the terms:
1 + -4x + -5x2 = 4x + -4x + 5x2 + -5x2

Combine like terms: 4x + -4x = 0
1 + -4x + -5x2 = 0 + 5x2 + -5x2
1 + -4x + -5x2 = 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
1 + -4x + -5x2 = 0

Factor a trinomial.
(1 + -5x)(1 + x) = 0

Subproblem 1

Set the factor '(1 + -5x)' equal to zero and attempt to solve: Simplifying 1 + -5x = 0 Solving 1 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5x = 0 + -1 -5x = 0 + -1 Combine like terms: 0 + -1 = -1 -5x = -1 Divide each side by '-5'. x = 0.2 Simplifying x = 0.2

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {0.2, -1}

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